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In the figure, DEFG is a square and angl...

In the figure, DEFG is a square and `angle BAC = 90^(@).` Prove that
(A) `Delta AGF`~ `Delta DBG`
(B)`Delta AGF`~`Delta EFC`
(C) `Delta DBG`~`Delta EFC`

Text Solution

Verified by Experts

The correct Answer is:
`Delta AGF~Delta EFC`
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