The perpenidicular drawn from the centre of a circle bisects any chord of the circle. The following are the steps involved in proving the above result. Arrange them in sequential order.

(A) Let `bar(OD) _|_ bar(AB)` .
(B) Let AB be the chord of the circle with centre O.
(C ) `Delta ODA -= Delta ODB` ( By RHS congruence property).
(D ) `OA =OB ` (radii), `OD= OD` ( common side) and `/_ ODA =/_ ODB =90^(@)`
(E ) `AD=DB` ( corresponding parts in congurents triangles ).

Options

A. 752 cu m
B. 805 cu m
C. 1016 cu m
D. 1214 cu m