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sin^(2) 60^(@) + 2 tan 45^(@) - cos^(2)...

`sin^(2) 60^(@) + 2 tan 45^(@) - cos^(2) 30^(@)`

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To solve the expression \( \sin^2 60^\circ + 2 \tan 45^\circ - \cos^2 30^\circ \), we will follow these steps: ### Step 1: Calculate \( \sin^2 60^\circ \) We know that: \[ \sin 60^\circ = \frac{\sqrt{3}}{2} \] Thus, \[ \sin^2 60^\circ = \left(\frac{\sqrt{3}}{2}\right)^2 = \frac{3}{4} \] ### Step 2: Calculate \( \tan 45^\circ \) We know that: \[ \tan 45^\circ = 1 \] Therefore, \[ 2 \tan 45^\circ = 2 \times 1 = 2 \] ### Step 3: Calculate \( \cos^2 30^\circ \) We know that: \[ \cos 30^\circ = \frac{\sqrt{3}}{2} \] Thus, \[ \cos^2 30^\circ = \left(\frac{\sqrt{3}}{2}\right)^2 = \frac{3}{4} \] ### Step 4: Combine all the values Now substituting these values into the original expression: \[ \sin^2 60^\circ + 2 \tan 45^\circ - \cos^2 30^\circ = \frac{3}{4} + 2 - \frac{3}{4} \] ### Step 5: Simplify the expression The \( \frac{3}{4} \) and \( -\frac{3}{4} \) will cancel each other out: \[ \frac{3}{4} - \frac{3}{4} + 2 = 0 + 2 = 2 \] ### Final Answer Thus, the value of the expression is: \[ \boxed{2} \] ---
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