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From a window 15 metres high above the ground in a street, the angles of elevation and depression of the top and the foot of another house on the opposite side of the street are `30^0a n d45^0` respectively show that the height of the opposite house is 23.66 metres `(t a k esqrt(3)=1. 732)`

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The correct Answer is:
`3.66` m
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From a window 15 metres high above the ground in a street,the angles of elevation and depression of the top and the foot of another house on the opposite side of the street are 30^(0) and 45^(0) respectively show that the height of the opposite house is 23.66 metres (take sqrt(3)=1.732)

From a window 60 m high above the ground of a house in a street, the angle of elevation and depression of the top and the foot of another house on the opposite side of the street are 60^(@) and 45^(@) respectively. Show that the height of opposite house is 60(1+sqrt(3)) metres.

Knowledge Check

  • From a window (h m high above the ground) of a house in a street, the angle of elevation and depression of the top and the foot of another house on the opposite side to the street are and 0, respectively. Then, the height of the opposite house is

    A
    `hcotthetacotphi`
    B
    `h(cotthetacotphi+1)`
    C
    `htanthetacotphi`
    D
    `h(tanthetacotphi+1)`
  • From the top of a house A in a street, the angles of elevation and depression of the top and foot of another house B on the opposite side of the street are 60^(@) and 45^(@) , respectively. If the height of house A is 36 m, then what is the height of house B? (Your answer should be nearest to an Integer.

    A
    91 cm
    B
    93 m
    C
    94 m
    D
    98 m
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