Home
Class 10
MATHS
In Figure 1, O is the centre of a circle...

In Figure 1, O is the centre of a circle, PQ is a chord and PT is the tangent at P. If angle POQ = 70°, then angleTPQ is equal to

Text Solution

Verified by Experts

The correct Answer is:
`35^@`
Promotional Banner

Topper's Solved these Questions

  • CIRCLES

    EDUCART PUBLICATION|Exercise SHORT ANSWER (SA-I) Type Questions|28 Videos

  • CIRCLES

    EDUCART PUBLICATION|Exercise SHORT ANSWER (SA-II) Type Questions|18 Videos

  • CIRCLES

    EDUCART PUBLICATION|Exercise OBJECTIVE Type Questions (Write True or False)|8 Videos

  • CBSE TERM-1 SAMPLE PAPER 2

    EDUCART PUBLICATION|Exercise Section -C|7 Videos

  • CONSTRUCTIONS

    EDUCART PUBLICATION|Exercise LONG ANSWER Type Questions|6 Videos

Similar Questions

Explore conceptually related problems

In the given figure ,'O is the centre of circle ,PQ is a chord and the tangent PR at P makes an angle of 50^(@) with PQ ,then anglePOQ is equal to :

In figure, if 0 is the centre of a circle, PQ is a chord and the tangent PR at P makes an angle of 50^(@) with PQ, then anglePOQ is equal to

In Fig , O is the centre of a circle , PQ is a chord and the tangent PR at P makes an angle of 50^@ with PQ. Find anglePOQ .

In the figure, O is the centre of a circle and AT is a tangent at point A. The measure of angle BAT is:

In Figure PQ is a chord of a circle with centre O and PT is a tangent. If QPT =60^@ so, find PRQ.

In figure PQ is tangent to the circle with centre at O at the point B , if angle AOB = 100^(@) , then angle ABP is equal to

In the adjoining figure, PQ is a chord of a circle and PT is the tangent at P such that angleQPT=60^(@). Find anglePRQ.