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To divide a line segment AB in the ratio...

To divide a line segment AB in the ratio 5:6, draw a ray AX such that `angleBAX` is an acute angle, the draw a ray BY parallel to AX and the points `A_(1),A_(2),A_(3),….." and " B_(1),B_(2),B_(3),…..` are located to equal distances on ray AX and BY, respectively. Then, the points joined are

A

`A_5 and B_6`

B

`A_6 and B_5`

C

`A_4 and B_5`

D

`A_5 and B_4`

Text Solution

Verified by Experts

The correct Answer is:
A
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