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The centroid of DeltaABC , where A(-4 , ...

The centroid of `DeltaABC` , where `A(-4 , 6)` , B (2, -2) and C(2,5) is :

A

(0,2)

B

(0,3)

C

(1,3)

D

(1,2)

Text Solution

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The correct Answer is:
To find the centroid of triangle ABC with vertices A(-4, 6), B(2, -2), and C(2, 5), we can use the formula for the centroid (G) of a triangle given by the coordinates of its vertices. ### Step-by-Step Solution: 1. **Identify the coordinates of the vertices:** - A = (x1, y1) = (-4, 6) - B = (x2, y2) = (2, -2) - C = (x3, y3) = (2, 5) 2. **Use the centroid formula:** The coordinates of the centroid (G) are given by: \[ G(x, y) = \left( \frac{x1 + x2 + x3}{3}, \frac{y1 + y2 + y3}{3} \right) \] 3. **Calculate the x-coordinate of the centroid:** \[ x = \frac{-4 + 2 + 2}{3} \] Simplifying this: \[ x = \frac{0}{3} = 0 \] 4. **Calculate the y-coordinate of the centroid:** \[ y = \frac{6 + (-2) + 5}{3} \] Simplifying this: \[ y = \frac{6 - 2 + 5}{3} = \frac{9}{3} = 3 \] 5. **Combine the x and y coordinates to find the centroid:** Thus, the coordinates of the centroid G are: \[ G(0, 3) \] ### Final Answer: The centroid of triangle ABC is \( G(0, 3) \).
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