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Solve for x and y, x + y = 2, x - y = 1...

Solve for x and y, x + y = 2, x - y = 1

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To solve the equations \( x + y = 2 \) and \( x - y = 1 \), we can follow these steps: ### Step 1: Write down the equations We have two equations: 1. \( x + y = 2 \) (Equation 1) 2. \( x - y = 1 \) (Equation 2) ### Step 2: Add the two equations To eliminate \( y \), we can add Equation 1 and Equation 2: \[ (x + y) + (x - y) = 2 + 1 \] This simplifies to: \[ 2x = 3 \] ### Step 3: Solve for \( x \) Now, divide both sides by 2 to find \( x \): \[ x = \frac{3}{2} \] ### Step 4: Substitute \( x \) back into one of the original equations Now that we have \( x \), we can substitute it back into Equation 1 to find \( y \): \[ \frac{3}{2} + y = 2 \] ### Step 5: Solve for \( y \) To isolate \( y \), subtract \( \frac{3}{2} \) from both sides: \[ y = 2 - \frac{3}{2} \] To perform the subtraction, convert 2 into a fraction: \[ y = \frac{4}{2} - \frac{3}{2} = \frac{1}{2} \] ### Final Solution Thus, the solution to the equations is: \[ x = \frac{3}{2}, \quad y = \frac{1}{2} \]
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