A triangular field right angled at A has length `AC=33m` and `AB=180m`. The area ( in sq m) of the field ABC is

Options

A. 2790 sq m
B. 2970 sq m
C. 3102 sq m
D. 3210 sq m

Answer

To find the area of the triangular field ABC that is right-angled at A, we can use the formula for the area of a triangle:

\[ \text{Area} = \frac{1}{2} \times \text{base} \times \text{height} \]

### Step-by-Step Solution:

1. **Identify the base and height**:
- In triangle ABC, we can take AC as the base and AB as the height.
- Given:
- AC = 33 m (base)
- AB = 180 m (height)

2. **Substitute the values into the area formula**:
\[ \text{Area} = \frac{1}{2} \times AC \times AB \]
\[ \text{Area} = \frac{1}{2} \times 33 \times 180 \]

3. **Calculate the product of base and height**:
\[ 33 \times 180 = 5940 \]

4. **Calculate the area**:
\[ \text{Area} = \frac{1}{2} \times 5940 = 2970 \text{ sq m} \]

### Final Answer:
The area of the triangular field ABC is **2970 square meters**.