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The distance of the B(6,6) from the orig...

The distance of the `B(6,6)` from the origin is:

A

` sqrt(53)` units

B

` sqrt(41) ` units

C

` sqrt( 72)` units

D

`sqrt(145)` units

Text Solution

AI Generated Solution

The correct Answer is:
To find the distance of the point \( B(6,6) \) from the origin \( O(0,0) \), we will use the distance formula. The distance \( d \) between two points \( (x_1, y_1) \) and \( (x_2, y_2) \) is given by: \[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \] ### Step 1: Identify the coordinates Here, the coordinates of the origin \( O \) are \( (0, 0) \) and the coordinates of point \( B \) are \( (6, 6) \). ### Step 2: Substitute the coordinates into the distance formula We will substitute \( (x_1, y_1) = (0, 0) \) and \( (x_2, y_2) = (6, 6) \) into the distance formula: \[ d = \sqrt{(6 - 0)^2 + (6 - 0)^2} \] ### Step 3: Simplify the expression Now, we simplify the expression inside the square root: \[ d = \sqrt{(6)^2 + (6)^2} \] Calculating the squares: \[ d = \sqrt{36 + 36} \] ### Step 4: Add the values Now, we add the values: \[ d = \sqrt{72} \] ### Step 5: Simplify the square root We can simplify \( \sqrt{72} \): \[ \sqrt{72} = \sqrt{36 \times 2} = \sqrt{36} \times \sqrt{2} = 6\sqrt{2} \] ### Final Result Thus, the distance of point \( B(6,6) \) from the origin \( O(0,0) \) is: \[ d = 6\sqrt{2} \text{ units} \] ---
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