In ` Delta ABC, angle B = 90^(@)` and d is the mid - point of BC. Prove that ` AC ^(2) = AD^(2) + 3CD ^(2)`

In a triangle ABC,B=90^(@) and D is the mid-oint of BC then prove that AC^(2)=AD^(2)+3CD^(2)

In the given figure ABC is a right angled triangle with angleB=90^(@) . D is the mid -point of BC . Show that AC^(2) = AD^(2) +3CD^(2) .

In right-angled triangle ABC in which /_C=90^(@), if D is the mid-point of BC, prove that AB^(2)=4AD^(2)-3AC^(2)

In Fig.3,ABC is a right triangle,right angled at C and D is the mid-point of BC.Prove that AB^(2)=4AD^(2)-3AC^(2)

In a right ABC right-angled at C, if D is the mid-point of BC, prove that BC^(2)=4(AD^(2)-AC^(2))

In a Delta ABC , angleB is an acute-angle and AD bot BC Prove that : (i) AC^(2) = AB^(2) + BC^(2) - 2 BC xx BD (ii) AB^(2) + CD^(2) = AC^(2) + BD^(2)

In an isoscles Delta ABC, AB= AC and D is a point on BC. Prove that AB^(2)-AD^(2)=BD*CD .

In triangle ABC , angle ACB = 90^(@) , CD bot AB and DE bot CB Prove that CD^(2) xxAC = AD xx AB xxDE .