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Simplify : 1 div { (1)/(2) + (1)/(3) + ...

Simplify : `1 div { (1)/(2) + (1)/(3) + (1)/(6) div ((3)/(4) - (1)/(3))}`

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The value of (3)/(5) xx 1 (7)/(8) div 1 (1)/(3) of (3)/( 16) - ( 3 (1)/(5) div 4 (1)/(2)" of" 5 (1)/(3) ) xx 2 (1)/(2) + (1)/(2) + (1)/(8) div (1)/(4)

[ 1 (1)/(4) div 1 (1)/(2) ] + [ 2 (1)/(3) xx 1 (3)/(4) ]=

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