`sqrt9 + sqrt16 = ?`

Simplify the following sqrt(-9) + sqrt(-16)

Represent sqrt(3. 5) , sqrt(9. 4) , sqrt(10. 5) on the real number line.

Represent sqrt(3. 5) , sqrt(9. 4) , sqrt(10. 5) on the real number line.

Find the value of :- (i) sqrt(4) (ii) sqrt(9) (iii) sqrt(16) (iv)sqrt(36)

Simplify: sqrt(-4) + sqrt(-16)- sqrt(-25)

If sqrtx+sqrt9=sqrt64 , what is the value of x ?

Using properties of proportion, solve for x : (i) (sqrt(x + 5) + sqrt(x - 16))/ (sqrt(x + 5) - sqrt(x - 16)) = (7)/(3) (ii) (sqrt(x + 1) + sqrt(x - 1))/ (sqrt(x + 1) - sqrt(x - 1)) = (4x -1)/(2) . (iii) (3x + sqrt(9x^(2) -5))/(3x - sqrt(9x^(2) -5)) = 5 .

a=9-4sqrt(5) , sqrt(a)-1/sqrt(a)=?

1/(sqrt(9)-\ sqrt(8)) is equal?

The value of x, x in (2,oo) where f (x) = sqrt(x sqrt(8x-16))+ sqrt(x- sqrt(8x-16)) is not differentiable is: