ABCD is a parallelogram. The diagonals AC and BD intersect each other at ‘O’. Prove that `ar(DeltaAOD) = ar(DeltaBOC)` . (Hint: Congruent figures have equal area)

In the figure, diagonals AC and BD of a trapezium ABCD with AB || DC intersect each other at O. Prove that ar(DeltaAOD) = ar(Delta BOC).

ABCD is a trapezium in which AB|\|DC and its diagonals intersect each other at point ‘O’. Show that (AO)/(BO)=(CO)/(DO) .

ABCD is a trapezium in which AB||DC and its diagonal intersect each other at point 'O'. Show that (AO)/(BO)=(CO)/(DO) .

The diagonals of a quadrilateral ABCD intersect each other at point'O' such that (AO)/(BO)=(CO)/(DO) . Prove that ABCD is a trapezium.

ABCD is a trapezium in which AB||DC the diagonals AC and BD are intersecting at E. IF DeltaAED is similar to DeltaBEC , then prove that AD=BC.

ABCD is a parallelogram, with AC, BD as diagonals, then overset(-)(AC)-overset(-)(BD) is equal to

In parallelogram ABCD, its diagonals overline (AC) and overline (BD) intersect at O. if AO=5cm then AC= ……… cm .

In the figure, ABCD is a quadrilateral. AC is the diagonal and DE || AC and also DE meets BC produced at E. Show that ar(ABCD) = ar (DeltaABE).

ABCD is a parallelogram. AC and BD are the diagonals intersect at O. P and Q are the points of tri section of the diagonal BD. Prove that CQ" ||" AP and also AC bisects PQ (see figure).

Draw two triangles ABC and DBC on the same base and between the same parallels as shown in the figure with P as the point of intersection of AC and BD. Draw CE || BA and BF || CD such that E and F lie on line AD. Can you show ar(DeltaPAB) = ar(DeltaPDC) Hint : These triangles are not congruent but have equal areas.