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ABC is a right triangle right angled at ...

ABC is a right triangle right angled at A. BCED,ACFG and ABMN are squares on the sides BC,CA and AB respectively. Line segments `AX bot DE` meets BC at Y and DE at X. Join AD,AE also BF and CM

Show that
`ar(BCED)=ar(ABMN)+ar(ACFG)`
Can you write the result in words? This is a famous theorem of Pythagoras. You shall learn a simple proof in this theorem in class X.

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