Take different values for x and find values of 3x + 5.

Take different values of x and values of 5 x + 1.

Now take x = 2, a = 1 and b = 3, verify the identity. • Take different values for x, a and b for verification of the above identity.

In a polynomial p(x)=x^(2) + x + 41 put different value of x and find p (x). Can you conclude after putting different value of x that p(x) is prime for all. Is x an element of N ? Put x=41 in p(x). Now what do you find ?

Find the value of 3x^2 if x=-1

If (x - p)/(x^(2) - 3x + 2) takes all real values for x in R then the range of P is

Find the value of x if 3x+45=34

Simplify the expression and find the value if x is equal to 5: 3(x+2)+5x−7

The angles of a triangle are (2x)^(@), (3x + 5)^(@) and (4x − 14)^(@) . Find the value of x and the measure of each angle of the triangle

If x^2-4x+3=1 then find the value of x.

If the polynomials 2x ^(3) + ax ^(2) + 3x -5 and x ^(3) + x ^(2) - 4x +a leave the same remainder when divided by x -2, find te value of a.