Now take x=2, a= 1 and b = 3, verify the identity (x + a) (x+b)=`x^2`+ (a+b)x+ab. Is it always LHS =RHS for all values of a and b?

Now take x=2, a= 1 and b = 3, verify the identity (x + a) (x+b)= x^2 + (a+b)x+ab.What do you observe? Is LHS=RHS?

Now take a = 1 and b = 3, verify the identity. (a+b)^(2)=a^(2)+2ab+b^(2) What do you observe? Is LHS = RHS ?

Show that f(x) = x^(3) + 3ax^(2) + 3a^(2) + b is increasing on R for all values of a and b.

Now take x = 2, a = 1 and b = 3, verify the identity. • Take different values for x, a and b for verification of the above identity.

Verify the identity: (a-b)^2 = a^2 -2ab + b^2 , where a= 3m and b = 5n.

Find : Verify the identity : (a - b)^(2) = a^(2) - 2ab + b^(2) , where a = 3m and b = 2m

Verify the identity (a+b)^2 = a^2 + 2ab + b^2 geometrically by taking a= 3 and b= 2.

Verify the identity (a+b) (a-b)= a^2 - b^2 geometrically by taking.a =3 units, b=2 units

Try to draw the geometrical figures for other identities. (x+a) (x+b)=x^2+(a+b)x+ab

Verify the identity (a-b)^2 = a^2 -2ab + b^2 geometrically by taking : a= 5 units, b = 2 units.