Consider `(x+p)(x+q)=x^(2)+(p+q)x+pq`
What identities you observed in your results ?

Consider (x+p) (x+q) = x^2 + (p+q)x + pq. Put q instead of 'p' what do you observe?

If p(q-r) x^2 +q(r-p) x+r(p-q) =0 has equal roots then 2/q =

In a polynomial p(x)=x^(2) + x + 41 put different value of x and find p (x). Can you conclude after putting different value of x that p(x) is prime for all. Is x an element of N ? Put x=41 in p(x). Now what do you find ?

|(x,p,q),(p,x,q),(p,q,x)|=

x (p-q) =____

IF the roots of the equation (1)/(x+p) +(1)/(x+q) =(1)/(r ) are equal in magnitude and opposite in sign , then p+q +r=

(p + q) ( p^2 - pq + q^2 ) = ____

For a gt 0, if the function f(x)=2 x^(3) - 9 a x^(2) + 12 a^(2) x + 1 attains its maximum value at p and minimum value at q such that p^(2) - q then a =