Find :
`(9m-Zn)^(2)`

Find : (9m-2n)^2

Find : (9m + 2n)^(2)

Find : (2m - 9n)^(2)

Find the product of (9m - n^(2))(-5mn)

If the value of equilibrium constant (K_f) for the operation Zn_((aq))^(2+) + 4OH_((aq))^(-) iff Zn(OH)_(4(aq))^(2-) is 10^(10x) , then x is (Given : Zn_((aq))^(2+) + 2e^(-) to Zn_((s)) , E^(@)=-0.76 V , Zn(OH)_(4(aq))^(2-) + 2e^(-) to Zn_((s)) + 4OH_((aq))^(-) , E^(@) = - 1.36 V , 2.303 (RT)/(F) = 0.06 )

Find: 9div2/5

Find: 2div8/9

Find 2-:(8)/(9)

For the redox reaction : Zn(s) + Cu^(2+) (0.1M) to Zn^(2+) (1M) + Cu(s) taking place in a cell, E_("cell")^@ is 1.10 volt. E_("cell") for the cell will be

Calculate the potential of a Zn -An^(2+) electrode in which the molarity of Zn ^(2+) is 0.001M. Given that E_(Zn^(2+)//Zn)^(0)=-0.76V R=0.314JK^(-1) mol ^(-1), F= 96500C mol ^(-1).