`2/sqrt6``xx``3/sqrt6` +`2/6`

4sqrt(6)xx3sqrt(24) = :-

Direction cosines of a line which passes through the points (1,2,3) and (-3,4,1) is A) (4/(2sqrt6), -2/(2sqrt6), 2/(2sqrt6)) B) (4/(2sqrt6), -2/(2sqrt6), -2/(2sqrt6)) C) (4/(2sqrt6), 4/(2sqrt6), 2/(2sqrt6)) D) (-4/(2sqrt6), 1/(2sqrt6), -2/(2sqrt6))

If t a ntheta=-1/(sqrt(5)) and theta lies in the IV quadrant, then the value of costheta is a. (sqrt(5))/(sqrt(6)) b. 2/(sqrt(6)) c. 1/2 d. 1/(sqrt(6))

(2) Find a and b if (5-sqrt6)/(5+sqrt6) =a+bsqrt 6

Distance between line r=i+j+k+lambda(2i+j+4k) and plane rdot(i+2j-k)=3 is (1) 4/(sqrt(6)) (2) 5/(sqrt(6)) (3) 1/(sqrt(6)) (4) 0 (5) 2/(sqrt(6))

If f(x)=sqrt(1+cos^2(x^2)),t h e nf^(prime)((sqrt(pi))/2) is (sqrt(pi))/6 (b) -sqrt(pi//6) 1//sqrt(6) (d) pi//sqrt(6)

If f(x)=sqrt(1+cos^2(x^2)),t h e nf^(prime)((sqrt(pi))/2) is (sqrt(pi))/6 (b) -sqrt(pi//6) 1//sqrt(6) (d) pi//sqrt(6)

(4(sqrt(6) + sqrt(2)))/(sqrt(6) - sqrt(2)) - (2 + sqrt(3))/(2 - sqrt(3)) =

Simplify : (sqrt(2))/(sqrt(6)-sqrt(2))- (sqrt(3))/(sqrt(6)+sqrt(2))

Let k be a real number such that the inequality sqrt(x-3) +sqrt(6 -x) ge k has a solution then the maximum value of k is sqrt3 (2) sqrt6 -sqrt3 (3) sqrt6 (4) sqrt6 +sqrt3