`if log [sece^x^2] then dy/dx =
(a) 2xe^x^2(tane^x^2)`
(b) ` 2xe^x^2(sece^x^2)(tane^x^2)`
(c)`x^2e^x^2tane^x^2 `
(d) `e^x^2 tane^x^2`

If y=log(sece^(x^(2))) , then (dy)/(dx) =

The solution of the equation ydx-xdy=x^2ydx is (A) y^2e^(-x^2/2)=C^2x^2 (B) y=Cxe^(x^2/2) (C) x^2=C^2y^2e^(x^2) (D) ye^(x^2)=x

int (e^x +2x)/(e^x+x^2) dx

(inte^x^4 (x+x^3+2x^5) e^x^2 dx) i se q u a lto 1/2x e^x^2e^x^4+c (b) 1/2x^2e^x^4+c 1/2e^x^2e^x^4+c (d) 1/2x^2e^x^2e^x^4+c

If xe^(xy)-y=sin^(2)x then (dy)/(dx) at x = 0 is

int(e^x(1+x))/(cos^2(x e^x))\ dx= (a) 2(log)_ecos(x e^x)+C (b) sec(x e^x)+C (c) tan(x e^x)+C (d) tan(x+e^x)+C

If y=(x+sqrt(x^2+a^2))^n ,t h e n(dy)/(dx) is (a) (n y)/(sqrt(x^2+a^2)) (b) -(n y)/(sqrt(x^2+a^2)) (c) (n x)/(sqrt(x^2+a^2)) (d) -(n x)/(sqrt(x^2+a^2))

The general solution of (dy)/(dx)=2xe^(x^(2)-y) is

If f(x)=e^(x)+2x , then f(ln 2)=

lim_(xrarr oo) (int_(0) ^(2x)xe^(x^(2))dx)/(e^(4x^2))