`[[Cosθ ,-Sinθ ],[Sinθ ,Sinθ ]]`

(cosθ-isinθ) ^ -n

cos^2θ - sinθ - 1/4 =0

compute. [(cosθ+isinθ)(cosθ−isinθ)]=?

Solve rsinθ=3 , r=4(1+sinθ) , 0≤θ≤2π.

The general value of the real angle θ, which satisfies the equation, (cosθ+isinθ)(cos 2 θ+isin2θ).(cosnθ+isinnθ)=1 is given by?

cosθ/ (1-tanθ) + sinθ/ (1−cotθ) is equals to ​

If a^2+b^2+c^2=1, then prove that |[a^2 +(b^2+c^2)cosθ, ab(1−cosθ), ac(1−cosθ)],[ba(1−cosθ),b^2(c^2+a^2)cosθ,bc(1−cosθ)],[ca(1−cosθ),cb(1−cosθ),c^2+(a^2+b^2)cosθ]| independent of a,b,c?

If cotθ+cosecθ=5 , find cosθ .

If 4sinθ+3cosθ=5 then tanθ=

If sinθ1+sinθ 2 +sinθ 3=3 , then cosθ 1+cosθ 2+cosθ3 is equal to