`x^2 - (sqrt 3 + 1) x + sqrt 3 = 0`

Complete the following activity to solve the quadratic equation sqrt(3) x^(2) +4x- 7 sqrt(3) = 0 by factorisation method : sqrt(3) x^(2) +4x- 7 sqrt(3) = 0 :. sqrt(3) x^(2) + square - 3x - 7 sqrt(3) = 0 :. x( sqrt(3) x + ) - sqrt(3) ( sqrt(3) x + 7) = 0 :. (" ") (x-sqrt(3))= 0 :. sqrt(3) x + 7 = 0 or square = 0 :. x = ( -7)/( sqrt(3)) or x = square :. (-7)/(sqrt(3)) and sqrt(3) are the roots of the equation.

Solve tan^2 x-(1+sqrt3)tan x+sqrt3=0

Solve x^(2)-(sqrt3+1)x+sqrt3=0 .

sqrt (2x) -sqrt (3y) = 0sqrt (3x) -sqrt (3y) = 0

The function y=f(x) is the solution of the differential equation [dy]/[dx]+[xy]/[x^2-1]=[x^4+2x]/sqrt[1-x^2] in (-1, 1), satisfying f(0)=0. Then int_[-sqrt3/2]^[sqrt3/2] f(x)dx is (A) pi/3 - sqrt3/2 (B) pi/3 - sqrt3/4 (C) pi/6 - sqrt3/4 (D) pi/6 - sqrt3/2