Find the center of circle
`(x+2)^2+(y+4)^2=16`

The centre of circle (x+2)^(2)+(y+4)^(2)=16

The Centre of Circle: (x+2)^(2)+(y+4)^2=16 is

Find the radical center of the circles x^2+y^2+4x+6y=19 ,x^2+y^2=9,x^2+y^2-2x-4y=5,

Find the centre and radius of circle 5x^(2)+5y^(2)+4x-8y=16.

Find the centre and radius of the circle 4x^(2) + 4y^(2) + 16y -4x = 19.

Find the area of the circle x^2+y^2=16 which is exterior to the parabola y^2=6x by using integration.

Find the area common to the circle x^2+y^2=16a^2 and the parabola y^2=6ax,agt0.

Find the locus of the-mid points of the chords of the circle x^2 + y^2=16 , which are tangent to the hyperbola 9x^2-16y^2= 144

Find the centre and radius of the circle 3x^(2)+ 3y^(2) - 6x + 4y - 4 = 0

Find the equation of the circle the end points of whose diameters are the centres of the circles x^2+y^2+16x-14y=1 and x^2+y^2-4x+10y=2