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(5(2x) - 7x)/15 = 2...

`(5(2x) - 7x)/15 = 2`

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(2x)/3 - (7x)/15 = ?

2x^2 + 7x - 15 = 0

(2x)/3 + 1 = (7x)/15 + 3

(a) Find the quare root of (x^(2) - 8x +15) (2x^(2) -11x + 5) (2x^(2) - 7x + 3)

30x^(2)+7x-15

I. 3x^(2) - 7x+2 = 0" " II. 2y^(2) - 11y + 15 = 0

(i) 7x^(2) + 16x - 15 = 0 (ii) 5y^(2)+ 8y - 21 = 0

Add: 5x^(2) - 7x + 3, -8x^(2) + 2x -5 and 7x^(2) - x - 2

Divide 4x^(2) + 7x - 15 " by " x +3

86 - [15x - 7 (6x - 9) - 2 {10x - 5 (2 - 3x)}]