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The expression Delta("subl")H^(Theta) =D...

The expression `Delta_("subl")H^(Theta) =Delta_(fus)H^(Theta) +Delta_(vap)H^(Theta)` is true at all

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The expression Delta_("sub"1)H^(Theta) =Delta_(fus)H^(Theta) +Delta_(vap)H^(Theta) is true at al

For which Delta_(f)H^(Theta) is zero?

H^(Theta) always act as

The temperature dependence of equilibrium constant of a reaction is given by ln K_(eq) = 4.8 -(2059)/(T) . Find Delta_(r)G^(Theta), Delta_(r)H^(Theta), Delta_(r)S^(Theta) at 298 K

The standard heat of formation of at 298 K for C Cl_(4)(g), H_(2)O(g), CO_(2)(g) and HCI(g) are -25.5, -57.8, -94.1 and -22.1 kcal mol^(-1) respectively. Calculate Delta_(r)H^(Theta) for the reaction C Cl_(4)(g)+2H_(2)O(g) rarr CO_(2)(g)+4HCl(g) Hint : Delta_(r)H^(Theta) = sum Delta_(f)H_("Products")^(Theta)- sum Delta_(f)H_("Reactants")^(Theta)

The temperature dependence of equilibrium constant of a reaction is given by In K_(eq) = 4.8 -(2059)/(T) . Find Delta_(r)G^(Theta), Delta_(r)H^(Theta), Delta_(r)S^(Theta) .

Statement-1: Lattice energy of BaSO_(4) is less than its hydration energy. Statement-2: |Delta_(L)H^(Theta)|&|Delta_(hyd)H^(Theta)| both are smaller.

Calculate Deltah for the eaction BaCO_(3)(s)+2HCI(aq) rarr BaCI_(2)(aq)+CO_(2)(g)+H_(2)O(l) Delta_(f)H^(Theta) (BaCO_(3)) =- 290.8 kcal mol^(-1), Delta_(f)H^(Theta) (H^(o+)) =0 Delta_(f)H^(Theta) (Ba^(++)) = - 128.67 kcal mol^(-1) , Delta_(f)H^(Theta)(CO_(2)) =- 94.05 kcal mol^(-1) , Delta_(f)H^(Theta) (H_(2)O) =- 68.32 kcal mol^(-1)

From the following data, calculate the standard enthalpy of formation of propane Delta_(f)H^(Theta) CH_(4) = - 17 kcal mol^(-1) Delta_(f)H^(Theta)C_(2)H_(6) =- 24 kcal mol^(-1), BE (C-H) = 99 kcal mol^(-1) (C- C) = 84 kcal mol^(-1) .

Find DeltaH of the process NaOH(s) rarr NaOH(g) Given: Delta_(diss)H^(Theta)of O_(2) = 151 kJ mol^(-1) Delta_(diss)H^(Theta) of H_(2) = 435 kJ mol^(-1) Delta_(diss)H^(Theta) of O-H = 465 kJ mol^(-1) Delta_(diss)H^(Theta) of Na -O = 255 kJ mol^(-1) Delta_(soln)H^(Theta)of NaOH = - 46 kJ mol^(-1) Delta_(f)H^(Theta) of NaOH(s) =- 427 kJ mol^(-1) Delta_("sub")H^(Theta) of Na(s) = 109 kJ mol^(-1)