If `sin theta = x and sec theta = y , then tan theta` `is ` (a) `xy` (b) `x/y` (c) `y/x` (d) `1/(xy)`

if sintheta = x and sectheta = y, then tantheta is : (a)xy, (b) x/y , (c) y/x , (d) 2/(xy)

If y=2 sin^(2) theta + tan theta then (dy)/(d theta) will be-

Find (dy)/(dx) when x = a sec theta and y = b tan theta

If x = a sec theta, y = b tan theta " then " (dy)/(dx) = ?

x =a tan theta ,y =b sec theta find dy/dx

If x +y= 3-cos4theta and x-y=4sin2theta then

If sin(theta-x) = a, cos (theta-y) = b , then cos(x-y) may be equal to :

The equation of the normal to the curve x=a\ cos^3theta,\ \ y=a\ sin^3theta at the point theta=pi//4 is (a) x=0 (b) y=0 (c) x=y (d) x+y=a

If x=sec theta-tan theta and y="cosec"theta+cot theta," then " y-x-xy=

If x=sectheta "and " y=cosec theta +cottheta , then prove that xy+1=y-x .