A metal oxide contains 32% oxygen and the vapour density of its chloride is 78.75. The atomic weight of metal is

Options

A. 157.5
B. 17
C. 51
D. None of these

Answer

C

Explanation

Let the valency of element by x. Its chloride will be `MCI_x`
Molecular weight of chloride= `2 xx VD `
`=2xx78.75`
`=157.5`
`thereforeM+ x xx35.5=157.5 `
The formula of medal oxide will be `M_2O_x`
`therefore` Percentage of oxygen `=(x xx 16)/(2M+ x xx61)`
`=(32)/100`
`x=4M//68`
Putting this value in Eq: (i),
`M+(4M)/(68)xx35.5=157.5`
`M=50.97=51`