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The specific heat of .an element is 0.03...

The specific heat of .an element is 0.031 cal/g/`""^(@)C`. 25.9 gofitreacts with `4 gO_2`. The atomic weight of element is

A

51.8

B

207.2

C

103.6

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
B

Specific heat `xx`Atomic weight = 6.4
`therefore` Atomic weight =`(6.4)/("Specific heat")`
`=(6.4)/(0.031)=207`
`because` 4 g oxygen combines with 25.9 g metal
`therefore` 8 g oxygen combines with
`=(25.9xx8)/4=51.8g`
The equivalent weight of metal= 51.8
Equivalent weight `xx` Valency =·Atomic weight
`therefore` Valency=`(207)/(51.8)=4`
`therefore` Atomic weight = `4 xx 51.8 = 207.2 `
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