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The additive and multiplicative inverse ...

The additive and multiplicative inverse of `1/4 + 1/3` is

A

`((11)/(30) , (30)/(11))`

B

`(( -7)/(12) , (12)/(7))`

C

`((11)/(20) , (-30)/(11))`

D

`((11)/(30), (-30)/(11))`

Text Solution

AI Generated Solution

The correct Answer is:
To find the additive and multiplicative inverse of \( \frac{1}{4} + \frac{1}{3} \), we will follow these steps: ### Step 1: Calculate \( \frac{1}{4} + \frac{1}{3} \) To add these two fractions, we need to find a common denominator. The least common multiple (LCM) of 4 and 3 is 12. \[ \frac{1}{4} = \frac{3}{12} \quad \text{(by multiplying numerator and denominator by 3)} \] \[ \frac{1}{3} = \frac{4}{12} \quad \text{(by multiplying numerator and denominator by 4)} \] Now we can add the two fractions: \[ \frac{1}{4} + \frac{1}{3} = \frac{3}{12} + \frac{4}{12} = \frac{3 + 4}{12} = \frac{7}{12} \] ### Step 2: Find the Additive Inverse The additive inverse of a number \( x \) is the value that, when added to \( x \), results in zero. For \( \frac{7}{12} \), the additive inverse is: \[ -\frac{7}{12} \] ### Step 3: Find the Multiplicative Inverse The multiplicative inverse of a number \( x \) is the value that, when multiplied by \( x \), results in one. For \( \frac{7}{12} \), the multiplicative inverse is: \[ \frac{12}{7} \] ### Final Answer Thus, the additive inverse of \( \frac{1}{4} + \frac{1}{3} \) is \( -\frac{7}{12} \) and the multiplicative inverse is \( \frac{12}{7} \). ---
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