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The incentre of triangle formed by lines...

The incentre of triangle formed by lines `x = 0, y = 0` and `3x + 4y =12` is

A

(3,1)

B

(1,2)

C

(2,1)

D

(1,1)

Text Solution

Verified by Experts

The correct Answer is:
D
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Knowledge Check

  • The incentre of the triangle formed by x=0,y=0 and 3x+4y=12 is

    A
    `(1/2,1/2)`
    B
    `(1,1)`
    C
    `(1,1/2)`
    D
    `(1/2,1)`

  • The equation of circumcircle of the triangle formed by the lines x = 0, y = 0, 2x + 3y = 5 is :

    A
    `6(x^2+y^2)+5(3x+2y)=0`
    B
    `x^2+y^2-2x-3y+5=0`
    C
    `x^2+y^2+2x-3y_5=0`
    D
    `6(x^2+y^2)-5(3x+2y)=0`

  • The equation of circumcircle of the triangle formed by the lines x = 0, y = 0, 2x + 3y = 5 is :

    A
    `6(x^2+y^2)+5(3x+2y)=0`
    B
    `x^2+y^2-2x-3y+5=0`
    C
    `x^2+y^2+2x-3y_5=0`
    D
    `6(x^2+y^2)-5(3x+2y)=0`

    • Similar Questions

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    The incentre of the triangle formed by the coordinates axes and 3x+4y=12 is

    " The area (in sq.units) of the triangle formed by the lines "x=0,y=0" and "3x+4y=12" is equal to "

    . If the area of the triangle formed by the straight lines x = 0 , y = 0 and 3x + 4y = a (a > 0) is 6 find the value of a .

    If the area of the triangle formed by the straight lines x = 0, y = 0 and 3x + 4y = a (a > 0) is 6, find the value of a.

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