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cos(A-B)=3/5 and tanA tanB = 2 then...

`cos(A-B)=3/5` and `tanA tanB = 2` then

A

cos A cos B = 1/5

B

cos A cos B = -1/5

C

sin A sin B = -2/5

D

sin A sin B = -1/5

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A
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