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A person of 60 kg enters-a lift going up...

A person of 60 kg enters-a lift going up with an acceleration `2 m^(- 2)`. The vertical upward force acting on the person will be `(g = 10 ms^(-2))`

A

600 N

B

720 N

C

620N

D

1200N

Text Solution

Verified by Experts

The correct Answer is:
B
Given, mass m = 60 kg, acceleration `a=2 ms^(-2)`
`:. w-mg = ma`
`impliesw=ma + mg = m(g + a) = 60 (10+2) `
`= 60 xx 12 = 720 N`
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