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A mass of 1 kg is hanged through a sprin...

A mass of 1 kg is hanged through a spring. The spring is stretched through 1cm. What is the energy stared in spring?

A

`0.449 J `

B

`0.049 J `

C

`4.9 J `

D

`49 J`

Text Solution

Verified by Experts

The correct Answer is:
B
Force `F = K . x` (restoring).
`1 xx 98 = K xx 1 xx 10^(-2)`
`K = (9.8)/(10^(-2)) = 980`
Potential energy conserved in the spring,
`U = 1/2 Kx^2 = 1/2 xx 980 xx 10^(-4)`
`= 490 xx 10^(-4) = 0.049 J`
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