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Two substances have masses 90 kg and 160...

Two substances have masses 90 kg and 160 kg respectively. They possess equal kinetic energy. The ratio of their momenta will be

A

`3/4`

B

`9/16`

C

`9/4`

D

`4/9`

Text Solution

Verified by Experts

The correct Answer is:
A
`because KE_1 = KE_1 therefore (m_1)/(m_2) = (v_2^2)/(v_2^1)`
`implies (v_1)/(v_2) = sqrt((m_2)/(m_1))`
Now , `(m_1v_1)/(m_2v_2) = (m_1)/(m_2) sqrt((m_2)/(m_1)) = 3/4`
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