Home
Class 12
PHYSICS
A boy throws a ball in air in such a man...

A boy throws a ball in air in such a manner that when the ball is at its maximum height he throws another ball. If the balls are thrown after the time difference of 1 s, then what will be the height attained by them?

A

19.6 m.

B

9.8 m

C

4.9 m

D

2.45 m

Text Solution

Verified by Experts

The correct Answer is:
C

`s= 0 xx 1 + (1)/(2) xx 9.8 xx (1)^(2) = 4.9" m"`
Promotional Banner

Similar Questions

Explore conceptually related problems

A boy throws a ball in air in such a manner that when the ball is at its maximum height he throws another ball. If the balls are thrown with the time difference 1 second, the maximum height attained by each ball is

A boy throws balls into air.He throws one, whenver the previous one is at its highest point. How high do the balls rise if he throws one ball each sec ?

A person can throw a ball vertically upto maximum height of 20 mt. How far can he throw the ball.

A ball of mass m is thrown vertically upwards. Another ball of same mass is thrown at an angle theta to the horizontal. If the time if flights for both is same, the ratio of maximum height attained by them

A boy throws n balls per second at regular time intervals. When the first ball reaches the maximum height he throws the second one vertically up. The maximum height reached by each bass is

A man throws ball into the air one after the other. Throwing one when other is at the highest point. How high the balls rise if he throws twice a second.

A juggler throws balls into air. He throws one when ever the previous one is at its height point. If he throws n balls each second, the height to which each ball will rise is