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Percentage of cationic vacancies in Fe(0...

Percentage of cationic vacancies in `Fe_(0.93) O` is:

A

0.0007

B

0.07

C

0.014

D

0.14

Text Solution

Verified by Experts

The correct Answer is:
B
Number of cationic vacancies = `1 - 0.93 = 0. 07%` of cationic vacancies = `0.07 xx 100 = 7%`
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