A certain quantity of an ideal gas is expanded from 20 L to 60 L isothermally in three steps. The pressure of these three states are 1.5 atm, 1.2 atm and 1 atm respectively. Now, the gas is brought back to the initial state by the given three steps again. Calculate the total work done on the system during this cycle in J. (Take: 1 atm - L = 100 J)

Answer

C

Explanation

So, the net work done on the system, will be the difference in the work done or the area enclosed by the cycle.
Total work done
`= 20 xx 1.5 "L atm" + 0.3 "L atm" + 0.2 xx 10 L "atm" = 35` L atm
`therefore 1 "atm L" = 100 J`
`therefore w_("total") = 3500 J`