The ionization enthalpy of Hydrogen atom is `1.312xx10^6 J "mol"^(-1)` . The energy required to excite the electron in the atom from `n=1 " to " n=2` is :

Options

A. `8.51xx10^5 J "mol"^(-1)`
B. `6.56xx10^5J "mol"^(-1)`
C. `7.56xx10^5 J "mol"^(-1)`
D. `9.84xx10^5 J "mol"^(-1)`

Answer

D

Explanation

given. `I.P. = 1.312xx10^6 J` mole
`E=E_2-E_1`
`= - 1.312xx10^6 xx 1/4 + 1.312xx10^6 xx1/1`
`E = 3/4 xx 1.312xx10^6`
`E =9.85xx10^5 J//"mole"`