How many litre of water vapor would be produced after the reaction of 10L of dihydrogen gas with 5L of dioxygen gas?

Answer

10

Explanation

`underset(2V)(2H_(2)(g))+underset(1v)(O_2(g))rarrunderset(2v)(2H_2O(g))`
According to Gay - Lussac.s law of gaseous volume, 2 volumes of dihydrogen react with 1 volume of `O_2` to produce 2 volumes of water vapour. Therefore, 10 volumes of dihydrogen on reaction with 5 volumes of dioxygen will produce 10 volumes of water vapour.