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Find out the molecular weight of C(6)H(5...

Find out the molecular weight of `C_(6)H_(5) COOH` in the case where, 1.22 g `C_(6)H_(5) COOH` is added into the solvent benzene and interpret the result. In 100 g benzene, `DeltaT_(b)`) = 0.13 and `k_(b) = 2.6` Kg/mol.

Text Solution

Verified by Experts

The correct Answer is:
244
`DeltaTb =0.13 =(2.6) (1.22//M)/((100)/(1000))`
`0.13 =2.6 xx (1.22)/(M) 10`
`M=2.6 xx (1.22 xx 10)/(0.13)`
`=244` g/mole
This value of molar mass suggest that benzoic acid `(C_(6)H_(5)COOH)` is dimerised in benzene
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When 1.22 g C_(6)H_(5)COOH is added into two solvents, the following data of DeltaT_(b) and K_(b) are obtained: i. In 100 g CH_(3)COCH_(3) , DeltaT_(b)=0.17 , K_(b)=1.7 kg K mol^(-1) . ii. In 100 g benzene, DeltaT_(b)=0.13 and K_(b)=2.6 kg K mol^(-1) . Find out the molecular weight of C_(6)H_(5)COOH in both cases and interpret the results.