The product of oxidation of I- with `MnO_4^(-)` in alkaline medium is:

Options

A. `ΙΟ_3^(-)`
B. `I_2`
C. `IO^(-)`
D. `IO_4^(-)`

Answer

A

Explanation

Since permanganate ion is oxidising agent.
In a basic medium, it oxidises iodide ions into iodate ions.
`MnO_4^(-) + I^(-) to IO_3^(-) + Mn^(+2)`