The mass of water produced from 445 g of `C_57 H_110 O_6` for the following reaction is:
`2 C_57H_110 O_6 (s) + 163O_2 (g) to 114 CO_2 (g) + 110H_2O (l)`

Options

A. 490 g
B. 890 g
C. 445 g
D. 495 g

Answer

D

Explanation

`C_57 H_110 O_6 + 163/2 O_2 to 57 CO_2 + 55H_2O`
Molecular weight of `C_57 H_110 O_6 = 890 `Moles of `C_57 H_110 O_6 = ("weight(gm)")/("Molecular weight")`
` = 445/890 = 1/2 `
According to stoichiometry
`because 1 "mole of " C_57 H_110 O_6` gives = 55 mole of `O_2`
`because` 1 mole of `C_57 H_110O_6 `gives = `55 xx 1/2 `mole of `H_2O`.
Wt. of `H_2O` = mole of `H_2O xx M `Wt. of `H_2O `
`= 1/2 xx 55 xx 18 = 495 g m`