If the solubility(s)of `AgCl_((s))` in 0.1M NaCl solution is a `X 10^(-9)` then what will be the value of a if the given solubility produce of AgCl is `1.6xx10^(-10)`?

Answer

`1.6`

Explanation

`AgCl_((s))hArrAg_((aq))^(+)+Cl_((aq))^(-)`
concentration `S" "S+0.1`
(S)
`K_(sp)=[Ag^(+)][Cl^(-)]`
`:.1.6xx10^(-10)=(S)(S+0.1)`
`:.1.6xx10^(-10)=Sxx0`
`.1( :. Slt lt 0.1)`
`:. S=1.6xx10^(-9)M`