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From the given below, the strongest redu...

From the given below, the strongest reducing agent has the standard electrode potential of -p Volt
`E_(Cr_(2)O_(7)^(2)//Cr^(3+))^(@) =1.33V , E_(CI_(2)//CI^(-))^(@) =1.36 V `
`E_(MnO_(4)^(-)//Mn^(2+))^(@) = 1.51 V , E_(cr^(3+)//cr)^(@)=-0.74 V `
Find out the value of p?

Text Solution

Verified by Experts

The correct Answer is:
`0.74`
Smaller the reduction potential value, greater is the reducing power.
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Using the data given below: E_(Cr_(2)O_(7)^(2-)|Cr^(3+))^(@)=1.33V E_(Cl_(2)|Cl^(-))^(@)=1.36V E_(MnO_(4)^(-)|Mn^(2+))^(@)=1.51V E_(Cr^(3+)|Cr)=-0.74V Find the most stable oxidised species.

Using the data given below: E_(Cr_(2)O_(7)^(2-)|Cr^(3+))^(@)=1.33V E_(Cl_(2)|Cl^(-))^(@)=1.36V E_(MnO_(4)^(-)|Mn^(2+))^(@)=1.51V E_(Cr^(3+)|Cr)=-0.74V Mark the strongest reducing agent.

Using the data given below: E_(Cr_(2)O_(7)^(2-)|Cr^(3+))^(@)=1.33V E_(Cl_(2)|Cl^(-))^(@)=1.36V E_(MnO_(4)^(-)|Mn^(2+))^(@)=1.51V E_(Cr^(3+)|Cr)=-0.74V Find the most stable ion in its reduced forms

Using the data given below: E_(Cr_(2)O_(7)^(2-)|Cr^(3+))^(@)=1.33V E_(Cl_(2)|Cl^(-))^(@)=1.36V E_(MnO_(4)^(-)|Mn^(2+))^(@)=1.51V E_(Cr^(3+)|Cr)=-0.74V Mark the strongest oxidising agent.

Using the data given below: E_(Cr_(2)O_(7)^(2-)|Cr^(3+))^(@)=1.33V E_(Cl_(2)|Cl^(-))^(@)=1.36V E_(MnO_(4)^(-)|Mn^(2+))^(@)=1.51V E_(Cr^(3+)|Cr)=-0.74V In which option the order of reducing power is correct?

Using tha data given below is reducing potenial. E_(Cr_2O_7^(2-)//Cr^(3+))^@ =1.33 V , E_(Cl_2//Cl^-)^@ =1.36 V E_(MnO_4^(-)//Mn^(2+))^@ =1.51 V , E_(Cr^(3+) // Cr)^@ =- 0.74 V find out which of the following is the strongest oxidising agent.

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