In a hydrogen atom, a Bohr's orbit has diameter of about 4. 232A. What is the maximum number of electrons that can be accommodated in the given shell?

Answer

8

Explanation

Diameter -4 . 232 A
`:.` Radius `-2 .116 A `
Now `r_(n) = 0.529 xx n^(2) A` [ for H - atom ]
`:. 2.116 = 0.529 xx n^(2) A `
`:. N^(2) -4 `
`:. N-2`
`:.` Maximum number of e- in the second shell
`= 2n^(2) = 2 xx (2)^(2)=8`