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Find the value of DeltaS of the folllowi...

Find the value of `DeltaS` of the folllowing reaction.
`2H_(2)(g)+O_(2)(g)to2H_(2)O(g)`.
Given, `DeltaH` and `DeltaG` are `-241.60kJmol^(-1)` and `-228.40kJmol^(-1)` of `H_(2)O` at 300 K.

A

4.4 kJ

B

`-88 kJ`

C

`+88 kJ`

D

`-44 kJ`

Text Solution

Verified by Experts

The correct Answer is:
B
`DeltaS=(DeltaH-DeltaG)/(T)=(-241.6-(-228.4))/(300)`
For 1 mole `H_(2)O=-44kJ`
For 2 moles =-88kJ
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