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For the circle x^(2) + y^(2) - 4x - 6y +...

For the circle `x^(2) + y^(2) - 4x - 6y + 11 =0`, find one end of the diameter if the other end is given by (3, 4).

A

(0,0)

B

(1,1)

C

(1,2)

D

(2,1)

Text Solution

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The correct Answer is:
C
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