A parallel plate capacitor of capacitanc...

A parallel plate capacitor of capacitance `1 mu F ` has a charge of `+ 2 mu C ` on one of the plates and a charge of `+ 4 mu C ` on the other. The potential difference developed across the capacitor is

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The correct Answer is:

`V = Q/C = (1 muC)/(1 muF) = 1` Volt

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