A particle of mass `m_(1)` moving with a velocity of 5 `ms ^(-1)` collides head on with a stationary particle of mass m2. After collision both the particle move with a common velocity of `4 ms^(-1)`then the value of `m _(1) // m _(2)`is :

Options

A. `4:1`
B. `2:1`
C. `1:8`
D. `1:1`

Answer

A

Explanation

By Conservation of momentum
`m _(1) (5) = ( m_(1) + m _(2)) 4`
` ( m_(1))/( m_(2)) = (4)/(1)`